A spherical steel ball has a mass of 3.475 g and a diameter of 9.40 mm. What is the density of the steel in g/cm3? The volume of a sphere = (4/3)πr3 Answer: 7.99 g/cm3
A spherical steel ball has a mass of 3.475 g and a diameter of 9.40 mm. what is the density of the steel? ( The volume of a sphere is - 14916579
Answer: Terminal velocity is Vt = √[2W/(ρACd) where W is the weight of the object, ρ is density of the fluid, A is the projected frontal area and Cd is the drag coefficient which depends on the shape and the surface roughness of the object. For a smooth spherical object (like a ball bearing), C...
Re: calculating the density of a sphere this is fairly simple to do say you where calculating the density of the earth first you would have to find the volume of the earth which is 26682593.6 then the formula for denstity which is density=mass ×volume mass = 5.97×10 to the power of 24 ta -da!!!!!
The formula for density is: σ= M/V. The equation for the volume of a sphere is as follows: V = 4/3•π•r³. The two formulas are combined in this calculator: σ= M/ (4/3•π•r³) NOTE: Identify possible substances based on the density by CLICKING HERE.
In simple terms, a sphere is a solid round ball. To calculate the mass of a sphere, you must know the size (volume) of the sphere and its density. You might calculate volume using the sphere's radius, circumference or diameter. You can...
2. 3 ⋅ 0.409. Weight = 5.782 pounds. Notice that only one inch increase in diameter caused a 4 pound increase in weight. This three inch diameter ball is more than triple the weight of the two inch diameter ball. Common Ball Material Density (Metric Units) Material. Density ( grams / cm³) 300 Stainless Steel.
Problem: A spherical ball of lead has a diameter of 5.0 cm.What is the mass of the sphere if lead has a density of 11.34 g/cm3? (The volume of a sphere is (4/3)πr3, where r is the radius.)
The ball is 1 inch diameter, 0.5 inch radius. The volume of a sphere is 4/3 pi r 3. The ball is 0.52 in 3. At 1 pound, your ball has a density of 1.92 lb/in 3. Steel is 0.28 lbs/in 3 Depleted Uranium is 0.69 lb/in 3. You sir have a ball of unobtanium!
A Spherical metal ball of radius 'r' is lying at the bottom of a stationary container containing liquid of density ρ as shown in the figure. Find the force exerted on the upper hemispherical portion of the sphere due to gauge pressure (P_0 = atmospheric pressure).
Two small spherical metal balls, having equal masses, are made from materials of densities ρ1 and ρ2(ρ1 = 8π2) and have radii of 1mm and 2mm, respectively. They are made to fall vertically (from rest) in a viscous medium whose coefficient of viscosity equals η and whose density is 0.1 ρ2. The ratio of their terminal velocities would be :
= 4.1887 cubic inches (is the volume of a 2 inch ball) 4.1887 times the density of lead, which is 0.409 pounds per cubic inch, gives a weight of 1.713 pounds. What would a three inch diameter lead ball weigh?
Answer (1 of 8): In case you were asking for the volume of a sphere, the formula for the volume of a sphere is V=frac{4}{3}pi r^3. To compute the density of a spherical object, you must weigh it. Then you divide its mass by its volume to get its density. Keep in mind that an object's density...
(a) A spherical steel ball (density p) of radius r falls under gravity through a vertical column of a fluid (density o < p) of coefficient of viscosity n. Will the ball attain constant velocity? If yes, under what condition ? Can this condition be used to find value of n? Justify giving the necessary expressions.
Ex 13.8,3 The diameter of a metallic ball is 4.2 cm. What is the mass of the ball, if the density of the metal is 8.9 g per cm3? To find mass, we have to find volume ...
A steel ball of 12 mm diameter is heated to 1225 K. It is then slowly cooled in the air to a temperature of 475 K. During the cooling process, the ambient temperature is 325 K and the heat transfer coefficient is 30 W/m2-K. Assume, the density of steel is 7800 kg/m3 and the specific heat is 600 J/kg-K.
A spherical metal ball of radius 'r' is lying at the bottom of a stationary container containing liquid of density p as shown in the figure. Find the force exerted on the upper hemispherical portion of the sphere due to Liquid. (P. = atmospheric pressure). 4 (A) 3 [3P +7rpg] B) en [ (B) tra - [3P+7rpg] 2 (C) r2 (3P+7rpg] (D) 2r [3P+7rpg]
MECHANICAL PROPERTIES OF FLUIDS. One spherical ball of radius R, density of released in liquid of density d//2 attains a terminal velocity V. Another ball of radius 2R and density 1.5 d released in the liquid will attain a terminal velocity. Watch 1 minute video.
Answer to: A spherical ball with a radius of 0.28 m is completely submerged in a fluid that has a density of 1.134 x 10^3 kg/m^3. (a) What is the...
The hollow metal ball has an outside diameter of 40 cm. Determine the wall thickness if the weight is 25 kg and the metal density is 8.45 g/cm 3. Hollow sphere The steel hollow sphere floats on the water plunged into half its volume.
A spherical metal ball of radius 'r' is lying at the bottom of stationary container containing liquid of density p as shown in the figure. The force exerted on the upper hemispherical portion of the sphere due to pressure (po = atmospheric pressure) is: 4r NI (A) [3P0 + 7rpg] (B) der 2 [3P0 + 7rpg 3 (C) 2 [3P + 7rpg] (D) 27ır?
Determine the mass, and then put the ball bearing in a known amount of water, and see what the increase in volume is (using cm3 or mm). Then do Mass divided by Displased Water, and you have density.
Density Of Spherical Steel Ball. A density of 7 is often quoted for mild steel as wellf you add alloying elements such as tungsten, chrome or manganese to improve the steel, the density will changeo the long answer is that the density of steel can vary 3.